PYTHON CODE
In a program, write a function that accepts two arguments: a list, and a number n. Assume that the list contains numbers. The function should display all of the numbers in the list that are greater than the number n. Output should look like:
As per your request, I have created this Python program. If
you're copying the program, make sure to have the same indents as
mine or you might encounter errors.
Here is the code:
n = int(input("Number:"))# accepts input from user
listofnumbers = [int(x) for x in input("List of
numbers:").split()]# accepts list from user
listgreaterthann = []# empty list to feed numbers greater than
input in listofnumbers
for x in listofnumbers:# for loop
if x > n and x not in listgreaterthann:
listgreaterthann.append(x)# appends number that are greater than
'n'
print("List of number that are larger than ", n, "are:") # prints
the list of number larger than 'n'
for x in listgreaterthann: # This for loop prints all the number in
the the list 'listgreaterthann'
print(x)# prints everthing in list
Here is the output:
First of all, this program accepts input 'n' from the user. This
input will be used as a base to check what numbers are greater than
it. Then we will have our list of numbers sumbitted by the user (
as requested by you) which will be stored in 'listofnumbers'.
This command "[int(x) for x in input("List of numbers:").split()]"
is used to take input from the user as a list.
Further, we'll create an empty list to store values later which
will be greater than the user input 'n'.
We'll create a 'for loop' that will determine whether a number will
fit into the list. If it already exists in the list, the program
will skip that number and only append the number which aren't
there.
"print("List of number that are larger than ", n, "are:")" will
prints the total elements greater than 'n'.
The for loop at the end prints all the values in
'listgreaterthann'
If you have any doubts, leave a comment below before rating. I'll happy to assist you further.
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