Question

+ -/0.83 points 11. Zumlntro7 15.P.045. What mass of the indicated solute does each of the following solutions contain? (a) 1.80 L of 13.6 M HCI solution 4.0 (b) 16.1 mL of 0.167 M NaOH solution 4.0 (c) 120. mL of 2.46 M HNO3 solution 4.0 g (d) 2.85 L of 0.590 M CaCl2 solution 4.0 g Need Help? Read It Watch It

Answer 1

a)

volume , V = 1.8 L

use:

number of mol,

n = Molarity * Volume

= 13.6*1.8

= 24.48 mol

Molar mass of HCl,

MM = 1*MM(H) + 1*MM(Cl)

= 1*1.008 + 1*35.45

= 36.458 g/mol

use:

mass of HCl,

m = number of mol * molar mass

= 24.48 mol * 36.46 g/mol

= 8.925*10^2 g

Answer: 892 g

b)

volume , V = 16.1 mL

= 1.61*10^-2 L

use:

number of mol,

n = Molarity * Volume

= 0.167*1.61*10^-2

= 2.689*10^-3 mol

Molar mass of NaOH,

MM = 1*MM(Na) + 1*MM(O) + 1*MM(H)

= 1*22.99 + 1*16.0 + 1*1.008

= 39.998 g/mol

use:

mass of NaOH,

m = number of mol * molar mass

= 2.689*10^-3 mol * 40 g/mol

= 0.1075 g

Answer: 0.108 g

c)

volume , V = 1.2*10^2 mL

= 0.12 L

use:

number of mol,

n = Molarity * Volume

= 2.46*0.12

= 0.2952 mol

Molar mass of HNO3,

MM = 1*MM(H) + 1*MM(N) + 3*MM(O)

= 1*1.008 + 1*14.01 + 3*16.0

= 63.018 g/mol

use:

mass of HNO3,

m = number of mol * molar mass

= 0.2952 mol * 63.02 g/mol

= 18.6 g

Answer: 18.6 g

d)

volume , V = 2.85 L

use:

number of mol,

n = Molarity * Volume

= 0.59*2.85

= 1.681 mol

Molar mass of CaCl2,

MM = 1*MM(Ca) + 2*MM(Cl)

= 1*40.08 + 2*35.45

= 110.98 g/mol

use:

mass of CaCl2,

m = number of mol * molar mass

= 1.681 mol * 1.11*10^2 g/mol

= 1.866*10^2 g

Answer: 187 g