Homework Answers
a) Molarity= no. Of moles of solute/V(L
7.5 = n/1.39 [n= number of moles]
n = 1.39 x 7.5 = 10.425
weight/molecular weight = no. of moles
weight = no. of moles x molecular weight
= 10.425 x 36.46
=380.09 g
b) 0.260 = n/(11.3/1000)
n = (0.26 x 11.3)/1000
= 0.002938
weight of NaOh = 0.002938 x 40
= 0.1175g
c)1.77 = n/(251/1000)
n = (1.77 x 251)/1000
= 0.44427
weight of HNO3 = 0.44427 x 63.01
= 27.99 g
d) 0.522 = n/ 3.65
n = 0.522 x 3.65
= 1.9053
weight of CaCl2 = 1.9053 x 110.98
= 211.45g
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