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This question has multiple parts. Work all the parts to get the most points. How many grams of solute are present in each of
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Answer #1

a)

volume , V = 5.75*10^2 mL

= 0.575 L

use:

number of mol,

n = Molarity * Volume

= 2.4*0.575

= 1.38 mol

Molar mass of HNO3,

MM = 1*MM(H) + 1*MM(N) + 3*MM(O)

= 1*1.008 + 1*14.01 + 3*16.0

= 63.018 g/mol

use:

mass of HNO3,

m = number of mol * molar mass

= 1.38 mol * 63.02 g/mol

= 86.96 g

Answer: 87.0 g

b)

volume , V = 1.65 L

use:

number of mol,

n = Molarity * Volume

= 0.284*1.65

= 0.4686 mol

Molar mass of C3H7NO2,

MM = 3*MM(C) + 7*MM(H) + 1*MM(N) + 2*MM(O)

= 3*12.01 + 7*1.008 + 1*14.01 + 2*16.0

= 89.096 g/mol

use:

mass of C3H7NO2,

m = number of mol * molar mass

= 0.4686 mol * 89.1 g/mol

= 41.75 g

Answer: 41.8 g

c)

volume , V = 3.2*10^2 mL

= 0.32 L

use:

number of mol,

n = Molarity * Volume

= 8.7*10^-3*0.32

= 2.784*10^-3 mol

Molar mass of CaSO4,

MM = 1*MM(Ca) + 1*MM(S) + 4*MM(O)

= 1*40.08 + 1*32.07 + 4*16.0

= 136.15 g/mol

use:

mass of CaSO4,

m = number of mol * molar mass

= 2.784*10^-3 mol * 1.362*10^2 g/mol

= 0.379 g

Answer: 0.379 g

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