Stuck on both problems A parallel plate capacitor is made up of two plates, each a...
A parallel plate capacitor is comprised of two metal plates with area A and separated by distance d. This parallel plate capacitor is connected to a battery with voltage AVo. Your answer should depend on A, d, ΔVo, and any other physical constants a. Determine the charge stored on the plates of the capacitor and the energy stored in the capacitor b. Determine the strength of the electric field between the plates of the capacitor c. An experimenter has five...
Problem l: (5 marks) An electric field is set up between two parallel plates, each of area A-20 m, by putting 0-1.0 HC of charge on one plate and-Q=-L0pCofchargean the other. The plates are separated by d 0mm with their centers opposite each other, and the charges are distributed uniformly over the suface of the plates 1) What is the magnitude of the electric field between the plates at a distance of 1.0 mm from the positive plate? (1.5 marks)...
The plates of a parallel plate capacitor are connected to a battery. Each plate has an area A. One plate has a net charge of +q. What is the magnitude of the electric field outside the capacitor? Note: ignore end effects at the edges of the capacitor. a) q e0 / A b) q / A*e0 c) e0Aq d) q e) zero N/C --- e is the correct answer but how
2. A parallel plate capacitor is submerged in a tank of water. Each plate is circular in shape with a radius of 5.0 cm, and the capacitors are placed 1.2 mm apart. a. (4 pts.) What is the capacitance of the capacitor? b. (3 pts.) If the capacitor is hooked up to a 12 V battery, what is the charge on each plate of the capacitor? C. (3 pts.) What is the electric field strength in the region between the...
A parallel plate capacitor is made of plates of area 0.05 m? each. The plates are separated by a distance of 0.200 mm. Initially, the space between the plates is filled with air. (a) What is the capacitance of this air-filled capacitor? (b) If the electric field inside the capacitor exceeds 3.00 x 106 V/m, the air undergoes electrical break- down. (This maximum field is known as the dielectric strength of air.) From this, calculate the maxi- mum voltage (potential...
31. The magnitude of the electric field between the plates of a parallel plate capacitor separated by 0.30 cm is 3.2x10' N/C. How does the field magnitude differ if: a) the charge on the plates were to double? b) the plate separation decreased by half the original distance? .610 6.14 loh.
Two charges are placed between the plates of a parallel plate capacitor. One charge is +q1 and the other is q2 = +4.58C. The charge per unit area on each plate has a magnitude of = 3.37 × 10-6 C/m2. The force on q1 due to q2 equals the force on q1 due to the electric field of the parallel plate capacitor. What is the distance r between the two charges?
Two charges are placed between the plates of a parallel plate capacitor. One charge is +q1 and the other is q2 = +4.56C. The charge per unit area on each plate has a magnitude of = 8.63 × 10-3 C/m2. The force on q1 due to q2 equals the force on q1 due to the electric field of the parallel plate capacitor. What is the distance r between the two charges?
Suppose that two plates are set up in parallel configuration with the top plate with an electric potential of 200V and bottom plate with an electric potential of 50 V. The plates are separated by a distance of 5 cm. (a) If the change in potential energy of a charge of magnitude X is 5 J when it is moved from the bottom plate to the top plate, find X. (b) What is the direction and magnitude of electric field...
Suppose that two plates are set up in parallel configuration with the top plate with an electric potential of 200V and bottom plate with an electric potential of 77 V. The plates are separated by a distance of 5 cm. (a) If the change in potential energy of a charge of magnitude X is 5 J when it is moved from the bottom plate to the top plate, find X. (b) What is the direction and magnitude of the electric...