A baggage handler drops your 7.90 kg suitcase onto a conveyor belt running at 1.50 m/s . The materials are such that μs = 0.570 and μk = 0.250. How far is your suitcase dragged before it is riding smoothly on the belt?
How far is your suitcase dragged before it is riding smoothly on the belt?
Sum of the horiz. forces = m*a = -friction
a = -friction/m
Sum of the vert. forces = 0 = N - m*g
N = m*g
friction = u*N = u*m*g
a = -uk*m*g/m = -uk*g
I am assuming that the suitcase is moving so kinetic friction will
be used. Once the bag has stopped moving, then you can use static
friction,
a = -uk*g
a = -0.25*9.81 = -2.452 m/s^2
using vf^2 = vi^2 + 2*a*d
vf = 0
d = -vi^2/(2*a) = -(1.50^2)/(2*-2.45) = 0.445 m
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