Question

Problem 2: The double angle is subject to tension load, dead load T,=400 kips, live load T=200 kips, and wind load T =500 kips. The double angle is connected to a 3/8" gusset plate with four A325-X bolt with diameter of /4" in standard bolt holes as shown in the figure below. Determine whether the double angle with such a connection can resist the given load or not. The double angle is 2L4x4x1/4. One angle's gross cross-sectional area A =1.94 in, a=2.5 in., b=2.5 in., c=1.0 in., e=1.09 in. OOOO falololol

Answer 1

Solülion: given that: Dead load Td = 400 kips Live load TL = 200 lips hind load The = 500 kips Ag = 1.94 in² a = 2.5 in b = 2.5 in c=1.0 in e = 1:09 in. a Luxq x'14 A = 1.94 in t='yin = googs Area Ag-20 = 1.94x2 Ag= 3.88 in² OOOO 11 Scanned with CamScanner

f = 3(3)= q in → Net Area: Ar= Ag-n dot diameler of bot do - Ž +¢ (do= 0.815 in An = 3.88 -1 (0.875) (4) (2) An= 3.442 lin2 Shear leg Factor 0-1- = 1-1.09 R0 - 0.8781 → Effective creasi te = Ancol 2 3.442 X0.8781 Ae= 3.025 int * Grade of material of angle are not given let Assume grade of steel fy = 50 44Si fee = 65 tdi Scanned with CamScanner

– Tensile Strength is yield; O ln = 0.9 fy Ag =0.9.250 x 3.88 = 174.6 lips → Tensile Strength in rupture: O ln = 0.75 Futte = 0.75 x 65 x 3.025 m2 = 147.46 Kips. → Strength connection → least of those two Idln = 147.46 kipsf Pue = 12 D+LEW = 1.2x400 + 200+500 Pu = 1180 kips To en <Pul The double angle can not resist the lead. Scanned with CamScanner