Two long parallel wires are separated by 5.11 cm and carry currents 1.63 A and 3.57...

Question

Question

Two long parallel wires are separated by 5.11 cm a

Answer 1

Answer #1

Given: seperation between wires (d) = 5.11 cm = 5.11*10^-2 m; currents through wires I₁ = 1.63 A and I₂ = 3.57 A

Now we know that the force acting per unit length of parallel wires is given by:

F = μ₀*I₁*I₂/2*π*d

Hence the force acting on the wire of length 3.15 m would be

F_net = 3.15*4π*10^-7*1.63*3.57/2π*5.11*10^-2 = 7.17*10^-5 N

Answer 2

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