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Use the iteration technique to find a Big-Oh bound for the recurrence relation belov Note you may find the following mathemat

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Answer #1

Let’s start with the recurrence relation, T(n) = 2 * T(n/3)+cn, and try to get it in a closed form.where T’ stands for time, and therefore T(n) is a function of time that takes in input of size ‘n’.

T(n) = 2T(n/3)+cn

we will find the Recursion depth that is How long (how many iterations) it takes until the sub problem has constant size.

The detailed solution is explained in the image given below:

(n)=21(3) ten... ||(143) =q1(733) T1123 . =QT(n/a) + ch / = [at(13/3) +.] tc. =41(14) +33 (n cu 42T (ap) + cha to catch = BI(

the last ferm a T (1) = alogno - log n toga f no then į s 50 Tin) = n lang at (0) + CH TWw=,173 +3cn Tini - Logos autch sunce

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