Considering our base condition as:
(i) T(1) = 1
The time equation given in question can be considered as follows:
(ii) T(n) = T(n-1) + C (where C = 5 and n > 1)
Now let's solve this recurrence relation and try to express it in terms of base condition.
Consider the equation (i), by replacing n by n - 1 we can say that,
(iii) T(n-1) = T(n-1-1) + C = T(n - 2) + C
Using equation (iii) in (ii) we can say that,
(iv) T(n) = T(n-2) + C + C = T(n-2) + 2C
Following the same way we can say that
T(n) = T(n-2) + 2C = T(n-3) + 3C = T(n-4) + 4C
Hence,
T(n) = T(n-K) + KC
To express in term of base condition T(1) = 1,
-> T(n - K) = T(1)
-> n - K = 1
-> K = n - 1
So T(n) can be written as,
-> T(n) = T(n-K) + KC = T(n-(n-1)) + (n-1)C
-> T(n) = T(1) + nC - C
-> T(n) = nC - C + 1 (as per base conditions)
As we can see T(n) is directly proportional to n, hence,
T(n) = O(n)
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