The first six terms are:
T(1)= 2
T(2) = 2*T(1)-1= 3
T(3) = 2*T(2) - 1 = 5
T(4) = 2*T(3)-1 = 9
T(5) = 2*T(4)-1= 17
T(6) = 2*T(5)-1 = 33
So, the first six terms are 2,3,5,9,17,33.
b. Closed form solution:
T(n)= 2*T(n-1) - 1
= 2*(2*T(n-2)-1)-1
= 2*(2*(2*T(n-3)-1)-1)-1
= 23T(n-3) -22- 2 - 20
= 23T(n-3) - (23-1)
= 2n-1T(n-(n-1)) - (2n-1-1)
= 2n-1T(1) - (2n-1-1)
= 2n-1*2- 2n-1 +1
= 2n- 2n-1 +1?
So, closed form solution is T(n)= 2n- 2n-1 +1?
NEED ASAP WILL RATE RIGHT AWAY 1,nEN s) (0 27.For thefollowing recurrence relation: T(1)2,T(n) 2(n1)z1,n a....
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