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5 and 6 please
5) Given the surface f(x, y, z) = 0 or z = f(x,y), find the tangent plane at P. a) z2 – 2x2 – 2y2 = 12 @ P=(1,-1,4) b) f(x,y)
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Answer #1

Fact: 1 Case-1 O If surface is given by f (xY2) then (af af af ay a normal vector Case TA If surface is given by Z= f(xy). af5) (a) Z²_2X²-2y²=12 =) Z?- 2.X2-272-12 =0 f (xyz) Normal Sa is 4*, - 445 7, 22) Case I at =( ig -tg4) N (-49458) 9 9 Ans tan3 b) gxy? 9 -1) - 9 9 f(x4) 2x - 3x43 Na (2- 2-343 ( Case - II at (2,-1) (55-18, -1) f72,-1) = to = 470 7. tangent plane at aNa S = 0, -1) f(3,5) = sin (IST) -1 = (20) tangent plane plane at p. is (0,0,-)).( x - 3,_Y-5, 2+1) = 0 2 + 1 6 x+y+z = 9 7²7© tangent plane at P is. (4,4,2.1: (x-2 s Y-29 Z-1) 4(x-2) + 4(7-2) + 212-1 =0 ०४ 2(x-2) + 2 (4-2) + 2-1 O CS Seated with Can

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