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If a vulnerability exists in 480 servers out of the first 900 tested, what is the...

If a vulnerability exists in 480 servers out of the first 900 tested, what is the probability of NOT finding the vulnerability in the 901st server?

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Answer #1

from given empriical data:

Probability of finding vulnerability in the 901st server =480/900 =8/15

therefore probability of NOT finding the vulnerability in the 901st server =1-8/15 =7/15

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