Question

how to find abs error of time 25 ?

help me fill out the blanks and show calculation of F centripetal...

Centripetal Force and Acceleration For a body in motion to ch force on a body is in the sa acceleration in that the speed i direction opposite to that of the velocit undergoing negative acceleration. In thes speed, not direction. In this lab we lo wdy in motion to change either its speed or direction, a force is required. When the net ody is in the same direction as the object's velocity, the force produces a positive in that the speed increases in the direction of the force. When the force acts in a site to that of the velocity, the object slows down. We then say it is decelerating or ve acceleration. In these cases, the effect of the force was to change the object's otion. In this lab we look at the kind of motion which results when the net force on the body is perpendicular to the object's velocity. was probably been discussed in lecture, the consequence of a force, which is constant in magnitude and always directed at right angles to the object's velocity, is uniform circular motion Any force that causes an object to follow a circular path is called a centripetal force, Centripetal force is not a new kind of force but is simply the name given to any force, whether string tension, gravitational, electrical, or whatever, that is directed at right angles to the path of the moving body and produces circular motion. If a body moves with uniform speed in a circle, it is said to be moving with uniform circular motion. Even though the speed is constant the velocity is continually changing, since the direction of the motion is constantly changing. Thus the body accelerates. It can be shown that the direction of the acceleration is always toward the center of the circle (see Hewitt, Chapter 7, or your lecture notes) and the magnitude of the acceleration is given by: Eq. 1...... where Vis the speed of the body and R is the radius of the circular path. Using Newton's Second Law (NSL) we can now easily find an expression for the force required to produce a given centripetal acceleration. Doing this gives: Eq.2....... Where is the centripetal force, m is the object's mass, and V and R are as defined above. In Part I of today's lab, you'll be spinning a known mass m, in a circle of measurable radius R, at constant speed V. mass m circular path The centripetal force, provided by a spring, is to be calculated using the equation g ing the equation given above. However, while m is given and R is easily measured, 16-1

Answer 1

- aul Salmo The absolute error in time depends on your measuring instrument, The abs error will be equal to the least count of your stop watch or other measuring motrunout that is used Now to calculate contripital force F, we should girst fined it frequency of and f= counter reading After - Before - 20844-20632 z8.48 Hz simillar dy caculate for Time mining two rows then take average of of then use for mulla for F = 47² frm to get centripital force 25