Centripetal Acceleration and Newton’s 2nd Law Lab
Q1. Starting with ar = v ^2 /r, show that for any object moving in a circle with constant centripetal acceleration ar pulling inwards, the theoretical rotation period is given by Pth = 2πr v = 2π r ar .
Q2. Does the rotation period change with increased tension in the way you would expect from theoretical grounds? If you increase the tension by pulling down on the hanging mass while the rubber stopper is rotating, what happens?
Q3. For motion in a vertical circle of radius r, use a free-body diagram to show that the minimum possible speed which will keep {a paperclip in contact with the cup / the cup on the tray / the string tension > 0} is given by € v ≥ rg.
Centripetal Acceleration and Newton’s 2nd Law Lab Q1. Starting with ar = v ^2 /r, show...
Objective: In this lab the Centripetal force required to maintain an object in uniform circular motion will be measured. The relationship between a rotating object's mass, velocity, and distance from the center of rotation to the centripetal force will be tested against theoretical expectations. Equipment: Centripetal Force Apparatus with 1, 2, 4oz weights, Force sensor, Magnetic field sensor, Short lab stand with cross bar, 500 g&1kg counter weights, scissors jack, "C" clamp Background: When an object is in uniform circular motion...
niform circular motion has a uniform speed v and carries an acceleration v-sq/radius such that the direction would change to give a circular path or trajectory raction for the case of satellite, contact force for the case of roller coaster, a string tension acting on a circulating blob, holding etc. The force to maintain the acceleration or the force causing the acceleration could be gravitational 6.67E-11 N meter-sa/ kg-sq Gravitational attraction F Gm1m2/distance/distance with G Kinetic equation vf'vf vo v+2a...
how to find abs error of time 25 ? help me fill out the blanks and show calculation of F centripetal... Centripetal Force and Acceleration For a body in motion to ch force on a body is in the sa acceleration in that the speed i direction opposite to that of the velocit undergoing negative acceleration. In thes speed, not direction. In this lab we lo wdy in motion to change either its speed or direction, a force is required....