Question

PRINTER VERSION <BACK NEXT Chapter 08, Problem 031 A block with mass m = 3.69 kg is placed against a spring on a frictionle incline with angle = 23.5° (see the figure). (The block is not attached the spring.) The spring, with spring constant k = 28 N/cm, is compresse 21.1 cm and then released. (a) What is the elastic potential energy of t. compressed spring? (b) What is the change in the gravitational potentia energy of the block-Earth system as the block moves from the release point to its highest point on the incline? (c) How far along the incline is the highest point from the release point? (a) Number Units (b) Number Units (c) Number Units Click if you would like to Show Work for this question: Open Show Work Question Attempts: Unlimited SUBMIT ANSWER

Answer 1

given m = 3.69 kg O = 23.5° K = 28 N - cm = 28 N, 2800NM 10²m x = 21.1 cm = 0.21lm 19 elastic Potential energy =£(2800)(0-2013? Tu= 62.3 J Answer Using work- eneagy The orom initial kinetic energy+ Work done by Spuing force P + work done by mgsino = final kinetic energy 0 + 62.3 (mg sino) (x+d) = 0 + de distance travelled by block I Just before Comming to rest mgsino (a + d ) = 62.3 (3-697(9.8) sin (23.5) (0.211 + d) = 62.3 [d=4.1m

sino = 1 / 2 x+d h= height raised =(x+d) sino : ( 411 + 4 ( ) sin(23-5) h=1672m. Change in Potential enengy = mgh = (3.69)(9.8) (1.72 ) = 62.2 I Answer *+ de 0-2 11 +4.1 24.311 m ( Anwer)