At a certain temperature, the Kp for the decomposition of H2S is 0.800.
H2S(g) H2(g) + S(g)
Initially, only H2S is present at a pressure of 0.236 atm in a closed container. What is the total pressure in the container at equilibrium?
H2S(g) <-----------------> H2(g) + S(g)
0.236 atm 0 0
0.236 - x x x
Kp = x^2 / 0.236 - x
0.800 = x^2 / 0.236 - x
x = 0.1906
PH2 = PS = 0.1906 atm
PH2S = 0.0454 atm
Ptotal = 0.427 atm
total pressure = 0.427 atm
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