At a certain temperature, the Kp for the decomposition of H2S is 0.782. H2S(g)−⇀↽−H2(g)+S(g) Initially, only...

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Question

At a certain temperature, the Kp for the decomposition of H2S is 0.782.

H2S(g)−⇀↽−H2(g)+S(g)

Initially, only H2S is present at a pressure of 0.289 atm in a closed container. What is the total pressure in the container at equilibrium?

Answer 1

Answer #1

Answer 2

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