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At a certain temperature, the Kp for the decomposition of H2S is 0.770 atm. H, S(g)...
At a certain temperature, the Kp for the decomposition of H2S is 0.710. H,S(g) = H, (g) + S(g) Initially, only H S is present at a pressure of 0.291 atm in a closed container. What is the total pressure in the container at equilibrium?
At a certain temperature, the Kp for the decomposition of H2S is 0.841 H,S(g) H2(g) + S(g) Initially, only H2S is present at a pressure of 0.127 atm in a closed container. What is the total pressure in the container at equilibrium? Number atm
At a certain temperature, the Kp for the decomposition of H2S is 0.851 . At a certain temperature, the Ky for the decomposition of H, S is 0.851. H, S(g) = H, (g) +S(g) Initially, only H, S is present at a pressure of 0.149 bar in a closed container. What is the total pressure in the container at equilibrium? Ptotal = 0.0195
At a certain temperature, the Kp for the decomposition of H2S is 0.800. H2S(g) H2(g) + S(g) Initially, only H2S is present at a pressure of 0.236 atm in a closed container. What is the total pressure in the container at equilibrium?
At a certain temperature, the Kp for the decomposition of H2S is 0.719. H2S(g)=H2(g)+S(g) Initially, only H2S is present at a pressure of 0.277 atm in a closed container. What is the total pressure in the container at equilibrium?
At a certain temperature, the Kp for the decomposition of H2S is 0.782. H2S(g)−⇀↽−H2(g)+S(g) Initially, only H2S is present at a pressure of 0.289 atm in a closed container. What is the total pressure in the container at equilibrium?
at a certain temperature, the Kp for the decomposition of H2S is 0.866 atm. Initially, only H2S is present at a pressure of 0.277 atm in a closed container. What is the total pressure in the container at equilibrium? H2S(g) H2(g) + S(g) P.S. it said .647 was incorrect
At a certain temperature, the Kp for the decomposition of H,S is 0.715 atm. H,S(g) - H, (g) + S(g) Initially, only H,S is present at a pressure of 0.117 atm in a closed container. What is the total pressure in the container at equilibrium? atm
At a certain temperature, the Kp for the decomposition of H2S is 0.828. At a certain temperature, the K_p for the decomposition of H_2S is 0.828. H_2(g) H_2(g) + S(g) Initially, only H_2S is present at a pressure of 0.269 atm in a closed container. What is the total pressure in the container at equilibrium?
At a certain temperature, the K, for the decomposition of H2S is 0.782. HS(g) = H2(g) + S(g) Initially, only H, S is present at a pressure of 0.260 atm in a closed container. What is the total pressure in the container at equilibrium? Ptotal = atm