At a certain temperature, the Kp for the decomposition of H2S is 0.851 .
At a certain temperature, the Kp for the decomposition of H2S is 0.851 . At a...
At a certain temperature, the Kp for the decomposition of H2S is 0.770 atm. H, S(g) = H,(g) + S(g) Initially, only H S is present at a pressure of 0.213 atm in a closed container. What is the total pressure in the container at equilibrium? Ptotal atm
At a certain temperature, the Kp for the decomposition of H2S is 0.828. At a certain temperature, the K_p for the decomposition of H_2S is 0.828. H_2(g) H_2(g) + S(g) Initially, only H_2S is present at a pressure of 0.269 atm in a closed container. What is the total pressure in the container at equilibrium?
At a certain temperature, the Kp for the decomposition of H2S is 0.800. H2S(g) H2(g) + S(g) Initially, only H2S is present at a pressure of 0.236 atm in a closed container. What is the total pressure in the container at equilibrium?
At a certain temperature, the Kp for the decomposition of H2S is 0.710. H,S(g) = H, (g) + S(g) Initially, only H S is present at a pressure of 0.291 atm in a closed container. What is the total pressure in the container at equilibrium?
At a certain temperature, the Kp for the decomposition of H2S is 0.841 H,S(g) H2(g) + S(g) Initially, only H2S is present at a pressure of 0.127 atm in a closed container. What is the total pressure in the container at equilibrium? Number atm
At a certain temperture the Kp for the decomposition of H2S is 0.714. At a certain temperature, the K, for the decomposition of HS is 0.714. H,S(g) + H,@) +S Initially, only H,S is present at a pressure of 0.207 atm in a closed container. What is the total pressure in the container at equilibrium? Pos-341 Enter numeric valu
at a certain temperature, the Kp for the decomposition of H2S is 0.866 atm. Initially, only H2S is present at a pressure of 0.277 atm in a closed container. What is the total pressure in the container at equilibrium? H2S(g) H2(g) + S(g) P.S. it said .647 was incorrect
At a certain temperature, the Kp for the decomposition of H2S is 0.754. Initially, only H2S is present at a pressure of 0.139 atm in a closed container. What is the total pressure in the container at equilibrium?
At a certain temperature, the Kp for the decomposition of H2S is 0.719. H2S(g)=H2(g)+S(g) Initially, only H2S is present at a pressure of 0.277 atm in a closed container. What is the total pressure in the container at equilibrium?
At a certain temperature, the Kp for the decomposition of H2S is 0.782. H2S(g)−⇀↽−H2(g)+S(g) Initially, only H2S is present at a pressure of 0.289 atm in a closed container. What is the total pressure in the container at equilibrium?