For:
4N2O --> 3N2 + 2NO2
apply:
multiply equation (3) by 2, since we need N2O2 with 4 coefficient
4N2O = 4N2 + 2O2 dG = (2)(-207.4) = -414.8 kJ/mol
2NO + O2 = 2NO2 dG = -71.2 kJ/mol
Add both equations
4N2O +2NO + O2 = 4N2 + 2O2 +2NO2 dG = -414.8 -71.2 = -486kJ/mol
4N2O +2NO = 4N2 + O2 +2NO2 dG = -414.8 -71.2 = -486kJ/mol
we need to get rid or NO, so add equaiton 2
4N2O +2NO = 4N2 + O2 +2NO2 dG = -414.8 -71.2 = -486kJ/mol
N2 + O2 = 2NO dG = 175.2
add all
N2 + O2 + 4N2O +2NO = 4N2 + O2 +2NO2+ 2NO dG =-486kJ/mol +175.2
4N2O = 3N2 + +2NO2 dG =-486 +175.2 = -310.8 kJ/mol
so..
dG = -310.8 kJ/mol
B)
2NO + O2 = 2NO2 dG = -71.2 kJ
so..
dG° = -RT*ln(K)
K = exp(-dG°/(RT))
K = exp(71200/(8.314*298)) = 3.024*10^12
2 NO(g) O2 (g) 2NO2 (g) Express your answer using two significant figures K- 1.06 Submit...
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