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Enter in the equivalent impedance as a numerical answer in a+bj format if ZR1=112, ZR2=1092, Zx1=12 j22, and Zx2=-3 j22. Zequ

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solution jXi amm 1X2 622 Zeq Given: ZR1 = 12, ZR2 =lor Zx1 = 1252 Zx 2 = -3; Let Z, = R + jx, = (1 + 125). and Z₂ = Zpr 11 Zx=) 2a = (1+2) + 3( 3 – 6 ) (3 + 108) (3-10 j) = (1+124) + 30 (3-103) = 1+12 % + qo - 300 j 709 109 Oo oo - 1 + 125 +0.8257 -2

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