Question

Letter answers to all on this page? Making a key for myself!

35. The infrared and proton NMR spectra for a compound are shown. What is its structure? 30. What is the major product of this reaction? CH OH, heat 31. Which compound will readily undergo both S,.2 and S.I reactions? Br C) Br What is the product of this reaction? 32. CH, (B) CH C) CH C ss. Which of these can withdraw electrons by both CH induction and resonance? A) -OCH, (B-Br (C -NO, (D) -NH, 36. What is the major organic 11B, 40℃ product of this- reaction? 34. Which reagent or set of reagents will best accomplish this transformation? A) OO 2) NaBHa D HOOH

Answer 1

Solution :-

for the reaction shown in the Q30 alkye halide is reacted with the strong base NaOCH3

the alkyl halide is the tertiary alkyl halide therefore it will follow the E1 reaction mechanism and forms the stable carbocation in the first step and then base abstracts the proton to form the more substituted alkene therefore it gives the product shown in the option A

reaction steps are shown in the following image.

For the Q 31 reactant shown in the option C will undergoo the sn1 and sn2 reactions radialy because the the carbocation can be stabilized by the resonance.

resonance structures are shown in the following image

For the Q 32

the addition of the Br2 is done on opposite side therefore tthe product shown in the option C wil be formed

For the Q 33 - NO2 group is the group which withdraw electrons by both inductive effect and resonance effect.

For the Q34 best reagent for the conversion of the alkene to more substituted alcohol is the Hg(OAc)2/H2O, NaBH4

because it gives the more substituted alcohol which is the desired product.

follwing image shows the reaction steps.