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Question 3: For the following network, determine the nodal admittance equation in matrix form. [Ybus] [V] = [1] f rom @ + + j
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Sola 13 Drawing the equivalent admittance nehwork You 16.6677jb15 Miza jiozjo: 2 y 3j33333 = og 26 T 12. -3.3332503 OVOTOT -Equivalent admittance Yzo -j1.667 -16667 420 = 71.3333 pu 440 .js + -16667 Y416 = -32.8571pu Writing eg 0, 0, ② and ③ in matrWriting eq O, 2, 3 & 4 in matrix form - Чч ч, | Чn+V,3 +Чич -Чn - Чіз - Чоч -Ч2 2 + Ч.5+420 -Чад с Чpx 1:40 -Чіз -23 Чуд+3+Substituting the values to determine YBUS Я» Чіо-+ 4 + Члч -6 - 67-5-3 333 : 15 Чn * – Чу2 = 6-40 7 - Яуз ? -Чіз = J5 дич - -

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