Question

1.50 mol of ice at-25 °C to liquid water at 55 c atlatm. What calculation would give the quantity of heat required by this process in J? The molar heat capacity of ice is 37.6 mol l-aC The molar heat capacity of liquid water is 75.4 J-mol C l. The heat of fision of water is 6.02 6.02 kJ 1000 J (A) g (1.50 mol) mol 37.6 J (B) (1.50 mol) (55 °C (-25 °C) mol OC 75.4 J (55°C-(-25 °C) (C) (1.50 mol) mol C 37.6 J 6.02 kJ (1.50 mol) (0 °C-(- 25 °C) (1.50 mob mol C mol 75.4 J (1.50 mol) (55 °C-0°C) mol OC 6.02 kJY 1000 J) 37.6 U (0 oC-(-25 °C) (1.50 mol) (1.50 mol) (E) q mol kJ mol C 75.4 J (55 °C-0°C) (1.50 mol) l mol

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