Question

5. 1/1 points Previous Answers MendStat15 6.2.025. Les z be a standard normal random variable with mean and standard deviation - 1. Find the percentile. (Round your answer to two decimal places.) 20.15 or the 85th percentile You may need to use the appropriate appendix table or technology to answer this question. Need Help? Read Woh Talk to a Tuter Viewing Seved Work Ravert to Last Response 6. 0/1 points Previous Answers MendStat15 6.2.039. and standard deviation a specified below. (Round your answer to four decimal places.) Answer the question for a normal random variable x with mean = 1.3 and 0 = 0.19. Find P(1.00 < x < 1.20). P(1.00<x< 1.20) You may need to use the appropriate appendix table or technology to answer this question. Need Help? Read teater Submit Answer Practice Another Version 7. /1 points MendStat15 6.2.040. Answer the question for a normal random variable x with mean and standard deviatione specified below. (Round your answer to four decimal places.) 1.2 and 0.15. Find PEx > 1.34). Pfx > 1.34) - You may need to use the appropriate appendix table or technology to answer this question. Need Help? Bardh to Tuter

Answer 1

u=13, 6=0.19 0.19 0.19 P(1.00<x<1.202= P(1.00-1-3 X-u < 01.20-113) =P(-1.58 <Z <-0.53) = P(Z <-0.53)-P(Z<-1158) = l-P(Z<0.53)-(1-P(Z <1:58)) = P(Z <1.58) P(Z20:53) = 0.9429-0.7019 = 0.2924. 3.) P(x= 1-34) 0.15 21-P(x<1-34) =1-P(x-u < 1.34-12) = l-P(Z <0.93) = -0.9238 = 0.0762. 1.) Plz<x) = 0.85 then a = 1.04 Cor) x=1.03.