Question

A random sample of -25 is selected from a normal population with me 102 and standard deviation (a) Find the probability that x exceeds 106. (Round your answer to four decimal places) - 10 (D) Find the probability that the sample mean deviates from the population mean - 102 by no more than 2. Round your answer to four decimal places) You may need to use the appropriate appendix table or technology to answer this question Need Help? al a h satu Subnet Answer Practice Another Version

Answer 1

Result:

a).

standard error = sd/sqrt(n) = 10/sqrt(25) = 2

z value for 106, z=( 106-102)/2 =2

P( mean x >106) = P( z > 2)

= 0.0228

Excel function used: =1-NORM.S.DIST(2,TRUE)

b).

we have to find probability such that P( 102-3 <mean x <102+3)

corresponding z values are -3/2=-1.5 and 3/2=1.5

= P( -1.5<z<1.5) = P( z <1.5) – P( z < -1.5)

= 0.9332 - 0.0668

=0.8664

Excel function used: =NORM.S.DIST(1.5,TRUE)

Excel function used: =NORM.S.DIST(-1.5,TRUE)