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A random sample of n = 45 observations from a quantitative population produced a mean x = 2.2 and a standard deviation s = 0.

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Answer #1

To test Ho :μ = 2.1 against H, :μ> 2.1

Rejection region :

T> 2.1+ *0.05, n-1}

or { i > 2.1 + 0.33 > 2.1+ *0.05,44)

or {T > 2.1+ 0.33 * 1.68023} V45

or, 1 > 2.182656)

Acceptance region : <2.182656}

i) B = P(Accept Ho when Ho is not true) = Pu=22(X < 2.182656)

=P=2* *22 2.182656 – 2:2 V45

= P(+44 2.182656 – 2.2 0.33 V45

= P(t44 < -0.3525669)

=0.3630482

03630

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