Question

The exposure index El for a 35 millimeter camera is a measurement of the amount of light that hits the film. It is determined

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Answer #1

EI = log2

here we have f=16, and t=4 seconds

162 EI = log2

El = log2 (256

EI = log2 (64)

El = log2 (20)

EI = 6 log, (2)

EI = 6(1)

El = 6

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now we have EI=-4. and t=16

--4 = log2

2^{-4}=2^{\log _2\left(\frac{f^2}{16}\right)}

2^{-4}=\frac{f^2}{16}

\frac{1}{16}=\frac{f^2}{16}

\frac{16}{16}=f^2

1=f?

fº=1

f=\sqrt{1}

{\color{Red} f=1}

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