ZuoTi.Pro
Question
  1. In the figure below, R=10kOhm, C=100pF and L=20mH. Calculate the resonance frequency of the circuit. 1. In the figure below, R=10kOhm, C=100pF and L=20mH. Calculate the resonance frequency of the circuit. (3) سکس با 10KOhm ا 2
science   physics   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

Resonance frequency of the Srcuit is gewen by f= 21 Le 22 We have L-200H L=20x103 4 = 2x 10²4 (= 10PF c=10x 10-12 F = 1x100Fround your answer as needed

0 0
Add a comment
Know the answer?
Add Answer to:
In the figure below, R=10kOhm, C=100pF and L=20mH. Calculate the resonance frequency of the circuit. 1....
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • Resonance in an R-L-C Circuit In an L-R-C series circuit, the resistance is 320 ohms, the...

    Resonance in an R-L-C Circuit In an L-R-C series circuit, the resistance is 320 ohms, the inductance is 0.300 henrys, and the capacitance is 1.80x102 microfarads. Part A What is the resonance angular frequency wo of the circuit? Express your answer in radians per second to three significant figures. Vie Available Hint(s) 1.29 10 rad/s wo Previous Answers Submit x Incorrect; Try Again; 5 attempts remaining Part B The capacitor can withstand a peak voltage of 560 volts. If the...

  • In a series R-L-C circuit, L = 0.215 H , C = 82.5 μF and the...

    In a series R-L-C circuit, L = 0.215 H , C = 82.5 μF and the voltage amplitude of the source is 260 V . 1)What is the resonance angular frequency of the circuit? 2)When the source operates at the resonance angular frequency, the current amplitude in the circuit is 0.595 A . What is the resistance R of the resistor? 3)At the resonance frequency, what are the peak voltages across the inductor, the capacitor, and the resistor?

  • 1.6 For the circuit shown, derive the resonance frequency and plot the resonance frequency behavior as...

    1.6 For the circuit shown, derive the resonance frequency and plot the resonance frequency behavior as a function of the resistance R. L = 10nH R C = 1pF

  • Experiment and Procedure CIRCUIT 1 10 kOhm 10 kOhm Vin) = 10kOhm 10kOhm V(out) FIGURE 10....

    Experiment and Procedure CIRCUIT 1 10 kOhm 10 kOhm Vin) = 10kOhm 10kOhm V(out) FIGURE 10. PROPORTIONALITY AND LINEARITY 1. Measure and verify all the individual 10 KA resistors shown in Figure 10, then build the given circuit 2. Vary the power supply from OV to 20V in 2V increments. Measure the corresponding output voltages for each input. 3. Calculate the corresponding proportionality constant that relates the output and input voltages. Use the equation: K = 4. Tabularize and plot...

  • The circuit shown in Figure 3 below shows a R-L-C series circuit with components R= 50...

    The circuit shown in Figure 3 below shows a R-L-C series circuit with components R= 50 , L = 1 H, and C= 250 uF. This circuit is connected in series to an AC current source ( il ) where instantaneous current is given by it = 28.29 Sin (100t) A. B + VR- C + VC - D ).4C Current source Figure 3 (a) Draw the circuit diagram for this circuit and mark the impedances (3 marks) (b) What...

  • For the circuit shown in Figure 3, when C = 1/16 F. L = 2 H...

    For the circuit shown in Figure 3, when C = 1/16 F. L = 2 H and R 42 the resonance frequency is given as W, 2 rads. For an input voltage source of 37 20° V with co applied to the circuit between a-b, the maximum energy stored in the capacitor, in J, is equal to: Figure 3

  • In an L-R-C series circuit, R = 260 ?, L = 0.820 H, and C= 0.0230...

    In an L-R-C series circuit, R = 260 ?, L = 0.820 H, and C= 0.0230 ?F. The source has voltage amplitude V = 150 V and a frequency equal to the resonance frequency of the circuit (a) What is the power factor? (b) What is the average power delivered by the source? (c) The capacitor is replaced by one with C = 0.0460 ?F and the source frequency is adjusted to the new resonance value. Then what is the...

  • In a series R-L-C circuit, R = 380 Ω , L = 0.330 H and C...

    In a series R-L-C circuit, R = 380 Ω , L = 0.330 H and C = 1.10×10−2μF . Part A What is the resonance angular frequency of the circuit? Part B The capacitor can withstand a peak voltage of 550 V . If the voltage source operates at the resonance frequency, what maximum voltage amplitude can it have if the maximum capacitor voltage is not exceeded?

  • In a series R-L-C circuit, L = 0.190 H , C = 84.5 μF and the...

    In a series R-L-C circuit, L = 0.190 H , C = 84.5 μF and the voltage amplitude of the source is 290 V . Part A What is the resonance angular frequency of the circuit? ω0 =   rad/s   SubmitMy AnswersGive Up Part B When the source operates at the resonance angular frequency, the current amplitude in the circuit is 0.610 A . What is the resistance R of the resistor? R =   Ω   SubmitMy AnswersGive Up Part C At...

  • An RLC circuit such as that of Figure (a) has R = 6.792, C = 18.3...

    An RLC circuit such as that of Figure (a) has R = 6.792, C = 18.3 uF, L = 1.38 H, and em = 24.4 V. (a) At what angular frequency od will the current amplitude have its maximum value, as in the resonance curves of Figure (b)? (b) What is this maximum value? At what (c) lower angular frequency wd1 and (d) higher angular frequency Wd2 will the current amplitude be half this maximum value? (e) What is (@d2...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT