Question

Air handling unit HVAC Analysis

known ambient air characteristics:
Relative humidity = 55%
air is 79% n2 and 21% o2
I have the mole fractions and the mass fractions entering the fan
the fan has a inlet pressure = atmospheric = 0 psig = 14.7 psia

fan characteristics:
fan duct = 4ft diameter
air mixture velocity = 14ft/second

the fan outlet pressure is 0.9 psig = 15.6 psia

with a known fan fluid efficiency of 60%
and know CV and CP values

how can I calculate the increase in Temperature of the air mixture using ideal gas laws? Thanks!

Answer 1

Inlet pressure P = 147 paia & 101.312 R Rareal fan duct = 4 ft diameter 8= 2 ft ration ( air mixture velocity = 14 ft /sec Outlet pressure = 15.6 pria elticency of fluid - 60% Cp & Ev value ① Increase in temp. mais flow rate inf o V. A - Density of Air = 14.69 psia D = 14.69.X-14X 3.14xY 2583.08 R. Humidity = 55% weight of water vapour in given amount of air I let annout of air is 100kg water vapour = 55 kg a = MCAT r- prentreration &= 12 - 15.6 Po 4.7 = 7.667

0.6 n = 60% = put in equ Job I-a 1.061) s y = 1.4 loc CP - 1.4 I Cp = lover Now Pv=nRT volume = IB-6283 P - 14.7 psia m=55 R = 10.7 31 ft Psi T ? 14.7 X 6.283 = 55X 10.731XT IT = 0.1560
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