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Problem 2: The figure below shows a two-member plane truss supported by a linearly elastic spring. The truss members are of a

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1. Solution: fixsk of al we shall mark Limk2 f link3 as in the link I P315KN limk! 50° link 2 tndkktapotngt diagram Given: E=glotal Now finding the apzing shikness for Link 3. =50x/03A1/m.. cos 0,-0 [32] Ginen kg sind,:l [32] -0:05 (3) Ky104 0.05 0.0where, -2.412 3.212 1.809 -2412 6.283 KAA- 10 6. 00.05 -3.2)2 2.५।2 2.412 9:500.-2:412 D. t8807 -KEp1 KAr- 10 -6.283 BB -2.4.. Dix-4.575 kN - - 10:931 kN. स् 2ay- 2x= -24.217KN -१, Nov, checking the equilibrium conditions, we haus, The resultant isSummary: The global displacement in x-direction is 3.8543m and in y-direction it is 11.1804m. The reaction forces of link1 in x-direction =14.575kN and in y-direction =-10.931kN.Reaction forces of link2 in x-direction=-24.217kN and in y-direction=0.Reaction forces of link3 in x-direction=0 and in y-direction=-0.559kN.

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