The more the entries are spread out, the greater the standard deviation.
In C1,C2,C3&C5 have symmetrical distribution about 12 but in C4 distribution asymmetrical.
Standard deviation of C4 can be calculated as:
(3*1+4*1+11*5+12*6+13*4+20*1+21*1)/19=11.94
=
similarly, it'll be followed for others.
Thus, the matching will be as follows:
8.59 | 7.29 | 1.07 | 4.08 | 1.60 |
C3 | C5 | C1 | C4 | C2 |
I hope this would help you, if you still have any doubt please let me know.
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