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between adjacent distance of 20.00 2 cm With a 66000 Hz tuning fork you measure a nodes. Is the value of c 340 m/s , what is
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Answer #1

For Theoretical value

Distance between 2 nodes = Half of wavelngth

                                         = 2

                                         =\frac{c}{2\nu }

                                          340 0.2575m 25.75cm 2x 660

Here , \lambda = wavelength , frequency

Now

Theoretical Experimental PercentError x 100 Theoretical

                                25.75 20 - x 25.75 X 100

                                = 22.33 %

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