Question

An online undergraduate business school uses a learning management software system (LMS) that allows instructors to know how many hours students are connected to the course website. When studying for the midterm exam, students have a choice of using two study guides. One study guide comes with the textbook and is professionally prepared by the publisher. The second study guide is prepared by the professor. Suppose the department chairperson is interested in determining whether a student's hours connected to the LMS (study time) is independent of the student's choice of study guide. The data available below show the numbers of students organized by study time and selected study guide. Determine whether the hours connected to the LMS is independent of the study guide the student chooses to use for the exam. Test at the alpha = 0.005 level using the p-value approach Click the icon to view the study guide data What are the null and alternative hypotheses for this test? O A. Ho: Study time and study guide have different proportions O B. Ho Study time and study guide have equal proportions 1 Study Guide Data HA: Study time and study guide have equal proportions HA: Study time and study guide have different proportions C. H0 : Study time is not independent of study guide Study Guide Chosen Publisher's Guide Professor's Guide HA: Study time is independent of study guide Ho: Study time is independent of study guide HA Study time is not independent of study guide Connect Time Under 6 hours 6-12 hours 12-20 hours Over 20 hours 144 157 118 146 145 155 113 118 O D. The test statistic is (Round to three decimal places as needed.) Print Done The p-value is (Round to three decimal places as needed.) What is the conclusion? O A. O B. Reject the null hypothesis. There is sufficient evidence to conclude that the two variables are not independent. Do not reject the null hypothesis. There is sufficient evidence to conclude that the two variables are not independent. C. 0 D. Reject the null hypothesis. There is insufficient evidence to conclude that the two variables are not independent. Do not reject the null hypothesis. There is insufficient evidence to conclude that the two variables are not independent.

Answer 1

The statistical software output for this problem is:

Chi-Square test: Statistic DF Value P-value Chi-square 3 2.0414229 0.5639

Hence,

Hypotheses: Option D is correct.

Test statistic = 2.041

P - value = 0.564

Conclusion: Option D is correct.