Question

A cycler is moving along a straight stretch of road after starting at/=0. The velocity of the cycle is given by the graph to the right. Assume that positive velocity represents when the cycle is moving away from its starting point and negative velocity represents when the cycle is moving toward its starting point. At what point in time was the cycle moving most rapidly? Explain your claim. At what point in time was the cycle at a maximum distance from its starting point? Explain your claim. Sketch a possible graph of the distance the cycle is from its starting point as a function of time. You don't need to include scale on your vertical axis, but label all significant times on your graph.

Answer 1

A)
P.S - The slope of a velocity-time graph represents the acceleration of the object.

From time t = 0 to t = 20 s, Cycle is moving most rapidly , as the acceleration is maximum btw that time , clearly evident from the slope of the graph.

B)
At t = 45 s, Cycle is at max distance from it's starting point. After this velocity turns negative and cycle starts moving back to it's starting point thus distance starts reducing.

C)

A- o 2 30 35 5 S