Question

At higher temperatures, dinitration of methylbenzoate is possible. Consider the directing effects of the ester group...

At higher temperatures, dinitration of methylbenzoate is possible. Consider the directing effects of the ester group and the first nitro group to predict the position of addition of the second nitro group. Draw the structure of the product of dinitration. Explain how the 1H NMR and 13C NMR would be different if this was product formed in this reaction.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

3 나. nu3 - ome i a mfa- pa iwil ( w T~k) het → (애 , ‘.tr<.1.#x.) 4 d LH (句 02 13 a dl 201 8-3-3 이 :43

Add a comment
Know the answer?
Add Answer to:
At higher temperatures, dinitration of methylbenzoate is possible. Consider the directing effects of the ester group...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • If a dinitration product were formed in the reaction, at what position on the ring would...

    If a dinitration product were formed in the reaction, at what position on the ring would the second nitro group be added?  Explain the reasoning behind your answer and draw relevant resonance structures to reinforce your rationale.

  • What is the splitting and integration for the protons indicated below? triplet, 2H multiplet (5), 1H...

    What is the splitting and integration for the protons indicated below? triplet, 2H multiplet (5), 1H singlet, 1H doublet, 1H triplet, 1H NH2 OOO The integration on a 'H NMR spectra containing three peaks is as follows for a molecule with the molecular formula C6H12O; A = 18, B = 12, and C = 6.0. How many hydrogens does peak B represent? OB = 12 B = 2 B = 6 B = 6.0 B=4 Draw the structure for 2,4Z-2-bromo-4-ethyl-2,4-hexandiene....

  • Chem 2320 extra credit assignment-12 points total Suppose that you were asked to perform the following...

    Chem 2320 extra credit assignment-12 points total Suppose that you were asked to perform the following alkoxymercuration reaction with (S)-3- vinylcyclopentanone using the standard alkoxymercuration conditions (steps 1 and 2) shown below. 1. Hg(OAc)2 CH3OH 2. NaBH4 Actual product Expected product Note: (S)-3-vinylcyclopentanone has two strong IR peaks at 1748 cm and 1642 cm iH NMR peaks at δ 2.5-3 ppm (7H), 5-6 ppm (3H), and a 13C NMR peak at 210 ppm. a. (3 pts) In the first box...

  • QUESTION 1 Any reaction involving a carbonyl group and a strong acid begins with the same...

    QUESTION 1 Any reaction involving a carbonyl group and a strong acid begins with the same first step, which is __________________ of the carbonyl oxygen. QUESTION 2 Using condensed molecular formulas (C#H#X#Y#) for your answers, predict the products of the reactions of C6H5CH2CHO (phenylacetaldehyde) with these reagents, and identify the functional group produced in the product. Note that the Tx symbol above allows you to do a subscript. a. NaBH4 / CH3OH b. 1. CH3MgBr; 2. H2O c. Ph3P=CHCH3 d....

  • pls and ty, (re-upload) alkene reactivity and its effects on stereo Reactivity In this module, we...

    pls and ty, (re-upload) alkene reactivity and its effects on stereo Reactivity In this module, we will look at alkene reactivity reacts with HBr, two products are formed, C and D. stereochemistry. When dode A CHE H-Br OCH, A OCH, Intermediate B OCH OCH C Question 1. (1 point) Draw the arrow pushing mechanism reactants are drawn below - just fill in the arrows. In electrophile (E) leaving group for the synthesis of C. The intermediates and each step. Identity...

  • Question 3 1s 3 ORTHO Today we learned about adding a second group to a mono-substituted...

    Question 3 1s 3 ORTHO Today we learned about adding a second group to a mono-substituted benzene ring. Any group on a benzene will affect the rate of the reaction (activated or deactivated relative to benzene) and the regioselectivity Where does the electrophile add? Ortho? Meta? Para? Some combination thereof? We found that EDGs (electron-donating groups) direct the electrophile to the ortho and para positions while EWGs (electron-withdrawing groups) direct the electrophile to the meta position. Now, it is time...

  • Can you help me identify reagent (i), Compound 8 and Compound 12 in the reaction scheme?...

    Can you help me identify reagent (i), Compound 8 and Compound 12 in the reaction scheme? You have laboratory data on all the compounds in the synthesis, however the amount of data available to you varies. Some have the entirety of the spectral data, others have as little as the elemental analysis. Use the laboratory data to help you discover which reaction has been performed. The lab data for Compound 8 and 12 is as follows: You can use any...

  • please answer all parts, thanks! 1. More substituted alkenes are more stable than less substituted alkenes....

    please answer all parts, thanks! 1. More substituted alkenes are more stable than less substituted alkenes. Show the orbital overlap that helps to explain this observation. 2. Why is the heat of hydrogenation for an alkene exothermic? Analyze the bonds that are changing. AH = -30 kcal/mol Explain: + H2 3. Treating alkene "A" below with HBr can lead to a number of products. "A" SM + H-Br A bunch of products. For real, hella products. 3.A. Label the stereocenters...

  • Help on all parts of question 3 would be greatly appreciated! 3. Treating alkene "A" below...

    Help on all parts of question 3 would be greatly appreciated! 3. Treating alkene "A" below with HBr can lead to a number of products. "A" + H-Br A bunch of products. For real, hella products. 3.A. Label the stereocenters in compound "A" as R or S and label the alkene as E or Z. 3.B. Draw the curved arrow mechanism leading to the most stabilized carbo- cation intermediate. (don't do any rearrangements, just acid/base with the alkene) H-Br most...

  • Experimental Outline In its simplest form, the aldol condensation is a self-addition involving tw...

    Organic Chemistry 2 Experimental Outline In its simplest form, the aldol condensation is a self-addition involving two molecules of the same aldehyde or ketone, in the presence of a base, and results in the formation of a new carbon-carbon bond joining the carbonyl carbon of one molecule to the a-position of the second. In many cases - if the reaction conditions aren't sufficiently mild - the initially formed aldol product reacts further in an elimination reaction to give what is...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT