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The ecom mended daly dictory allowance or zn c among males older than age S0 years s 15 mg/d y. An article reports tne ollo population of ell males age GS-4 fells below the recommended allowance? (Use a0.05.) Stete the appropriate nu and aternetive hypotheses ng summary data on intake for a sample o malege 65-74 years ? 11S, 11.1 and s 6.90. Does the cata indicate that overage ca y zinc ntake in the MO: ?-15 Ha: 15 Ho : ? * 15 Calculate the test statistic and determine the P-value. (Round your test stabstic to two decimel places and your A-value to four decimal places.) Pvaluc- State the conclusion in the Do not reject the nul hypothesis. Thero ¡s sufficient cviccnce that average caily zinc intake falls below 15 mg/day. Reject the null hypathesis, There is suflicent evidence that average daily zine intake falls below 15 mg/day Do not reject the nul hypcthesis. There is nat sufticient evidence that average daily zinc intake falls below 15 mg/day. Reject the null hypathesis. There is not sufficient evidence that average daily nc intake fals bellow 15 mg day.

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Hypothesis test H0 : μ > 15 Ha : μ < 15 (Null Hypothesis, Ho : μ-15 is also correct) (Alternative Hypothesis, also called H1P-value 0.0000 test statistic-6.06 P-value-P(Z <-6.06) 0.0000(from z-table) P-value 0.0000 Rejection Rule: Reject Ho if p-val

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