Given that,
EHCL = 0..0380 V
EX = 0.0530 V
[X+] = 0.0520 M
Let's consider the Nernst equation ,
E = E0 - (0.0591/n)*log Q
E = E0 - (0.0591/n)*log(1/[X+]) . --------(1)
0.0380 = E0 - (0.0591/1)*log(1/0.0520)
0.0380 = E0 - 0.0756
E0 = 0.11
Now, substitute the above value in eq(1)
E = E0 - (0.0591/n)*log(1/[X+])
0.0530 = 0.11 - (0.0591/1)*log(1/[X+])
0.964 = log(1/[X+])
1/[X+] = 100.964
1/[X+] = 9.20
[X+] = 0.108 M
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