2. Use Ohm's Law and Kirehhoffs laws to a) find the value of R in the...
Problem 2. Use Kirchhoff's laws and Ohm's law to find the voltage vo as shown in following figure. 5Ω b 500 V 5i
. Use Ohm's law and voltage division to find the power supplied by the source and power dissipated in 60 and 8Ω resistors. 1.2Ω 4Ω 20 A 2Ω 8Ω 12Ω
here is the problem Use Ohm’s law and Kirchhoff’s laws to find thevalue of R in the circuit shown Use Ohm's law and Kirchhoff's laws to find the value of R in the circuit shown.
Problem 4. Use Kirchhoffs laws and Ohm's law to calculate the current i2 flowing across the 6k2 resistor and V2in Figure 3. Show all the work. 54k1V 2 kC2 30i 8V Figure 3
Pre-lab EM-5 Ohm's Law and Kirchhoff's Rules Ohm's Law The resistance R of a device can be determined by either directly measuring the resistance using an ohmmeter, or by measuring the current I through it and the voltage Vacross it, and then calculating R using Ohm's Law V R= (1) If the voltage across a resistor is 10V, and the current passing through it is 2.5 mA. of the resistor? What is the resistance R= Ω. Kirchhoffs Loop Rule Around...
For the circuit shown, using resistor combinations and Ohm's Law, calculate (a) Vo and b, (b) the power dissipated in the 15 ? resistor, and (c) the power developed by the voltage source. 2? 15 ? 120 V
3-3: Use KVL/KCL and Ohm's Law as needed to find the values of v1 and v2. You must show separate KCL and KVL equations, no credit will be given if other methods such as nodal analysis are used. 80 80 Ω υ,Σ 120 Ω V140 6 A
I1=1.3a J Laws an power developed is equal to the total power dissipated ped ws and Ohm's Law to find the current through each branch. Show that the total 70 70 60 181V 10is 50 20
Is1 15 mA R. 1ΚΩ In the circuit shown, use KCL, KVL, and Ohm's Law to find the two resistor currents R1 R2 K. S2 25 V 0.5 kΩ 5 mA iR2 1R2 =
TION 3-2 Application of Ohm's Law 4. Determine the current in each case. (a) V= 5 V, R = 1.012 (c) V 50 V, Rm 100Ω (e) V = 250 V, R = 4.7 MS2 (b) V = 15 V, R= 10 Ω (d) V = 30V,R = 15kΩ