Question

I1=1.3a

J Laws an power developed is equal to the total power dissipated ped ws and Ohm's Law to find the current through each branch. Show that the total 70 70 60 181V 10is 50 20

Answer 1

Given circuit 70 times 70/70 + 70 = 35 - 181 + 35i_1 + 50 (i_1 - i_2) = 0 - 181 + 35i_1 + 50i_1 - 50i_2 = 0 85i_1 - 50i_2 = 181 given i_1 = 1.3 85 (1.3) - 50i_2 = 181 50i_2 = 85 (1.3) - 181 50i_2 = 110.5 - 181 50i_2 = -70.5 i_2 = -70.5/50 i_2 = -1.41 \r\n - 10i_5 + 80 i_2 + 50 i_2 - 50 i_1 = 0 10 i_s = 130 i_2 - 50 i_1 10 i_s = 130 (-1.41) - 50 (1.3) = -183.3 - 65 10 i_s = 248.3 i_s = 24.83 p_d diverted_(181v) = VI = (181) (1.3) = 235.3 p_absorbed_35_Ohm = I^2 R = (1.3)^2 times 35 = 59.15 p_absorbed_50 Ohm = 50 times (2.71)^2 = 367.205 p_absorbed_80 Ohm = 80 (1.41)^2 = 159.048 p_deliver_10i_s = 350.103 p_delivered = p_delivered_(181v) + p_delivered_10i_s = 235.3 + 350.103 = 585.403 waltz p_delivered = 585.403 waltz p_absorbed = p_absorbed 80 Ohm + p_absorbed 50 Ohm + p_absorbed 35 Ohm
I hope that you understand.

If you have any doubt please comment in the below comment section.

You like this answer please rate this.