The voltage for the following cell is +0.731 V. Find Kb for the organic base RNH2....

Question

Question

The voltage for the following cell is +0.731 V. Find Kb for the organic base RNH2.

Use E(SCE)= 0.241V.

Pt(s)│H2(1.00 atm)│RNH2(0.100M), RNH3+(0.0500M)║SCE

Answer 1

Answer #1

For the given reaction -

R-NH₃⁺ (aq) <----------> R-NH₂ (aq) + H⁺ (aq)

Since - E_cell = -(0.0592/n) log K_a

Where, E_cell = 0.731 - 0.241 = 0.490 V

Therefore, 0.490 = -(0.0592/1) log K_a

Therefore, K_a = 5.30*10^-9

Thus, K_b = K_w/ K_a = (1.0*10^-14 / 5.30*10^-9) = 1.892*10^-6

Answer 2

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