Question

e table shows the results of a survey of patrons of a particular restaurant chain. Good Service 538 Poor Service 329 Meals Lunch Dinner Total Total 867 329 973 634 1607 15119632474 If one of these patrons is selected at random, find the probability that their service was good, given that their meal was lunch The probability that their service was good, given that their meal was lunch, is (Round to four decimal places as needed.)

Answer 1

Hello

Q - 1 -

$P(Good\mid Lunch)=\frac{538}{867}=0.6205$

Q - 2 -

$\\ P(A \cup B)=P(A)+P(B)-P(A \cap B) \\ P(A)=0.7+0.2-0.4 = 0.5$

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