Question

Use z scores to compare the given values. In a recent awards ceremony, the age of the winner for best actor was 38 and the age of the winner for best actress was 48. For all best actors, the mean age is 47.7 years and the standard deviation is 7.2 years. For all best actresses, the mean age is 32.6 years and the standard deviation is 10.5 years. (All ages are determined at the time of the awards ceremony.) Relative to their genders, who had the more extreme age when winning thm award, the actor or the actress? Explain. and the z score for the actress is z= the had the more extreme Since the z score for the actor is z = age. (Round to two decimal places.) actor actress Enter your answer in each of the answer boxes. ?

Answer 1

$For\ Actors\\ x = 38 \\ \bar x = 47.7 \\ \sigma = 7.2 \\ So \ Z = \frac{X - \bar x}{\sigma} = \frac{38- 47.7}{7.2} = 1.3472$

$For\ Actresses\\ x = 48 \\ \bar x = 32.6 \\ \sigma = 10.5 \\ So \ Z = \frac{X - \bar x}{\sigma} = \frac{48- 32.6}{10.5} = 1.4667$

So Z score for actor = 1.35 and z score for actress = 1.47 So the actress has more extreme z value.

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