Question

Scenario 1 As the food court manager at the Mall of Elbonia, you want to determine how much time customers spend at the mall at different times of the week (for example: midweek, day; midweek, evening; weekend, day; weekend, evening). Last week, the mall survey staff administered a random survey to mall visitors by selecting customers as they were leaving the mall. One of the questions asked was how much time the customer had spent in the mall on that day. The findings from this study are provided in the Mall Time Interview Results file. In this file, Columns A through D show the time spent by the customers interviewed, according to the weekday and time of day when the interviews occurred. Is there any statistically significant difference (at alpha = .05) in the average amount of time people spent in the mall, based on the weekday and time? To determine the answer to that question, you need to complete the following: Identify the null and alternative hypotheses you should form for this test. State each as a written explanation and as a math equation. Identify the appropriate statistical test you should use to accept or reject the null hypothesis. Calculate the appropriate ANOVA values to accept or reject your null and alternative hypotheses. What should you tell the operators of the Mall of Elbonia's food court stores (in terms of the mall's high-traffic times and customer tendencies)? Summarize your statistical analysis in a report for management. Midweek, Day Midweek, Evening Weekend, Day Weekend, Evening 66 64 64 185 78 71 121 207 66 174 29 203 32 53 147 84 35 52 162 125 34 96 108 184 88 135 61 129 149 142 77 94 86 149 88 182 145 59 131 65 146 82 127 110 38 118 141 139 95 132 176 108 80 81 161 117 106 111 3 125 42 68 82 65 95 22 128 47 77 50 51 88 98 125 81 84 71 105 54 165 122 92 161 86 125 115 158 164 85 148 45 199 97 66 134 83 33 74 38 36

Answer 1

A	B	C	D	E	F	G	H	I
ANOVA single factor
summary
Groups	count	sum	average	variance
Midweek, day	25	2089	83.56	1292.757
Midweek, evening	25	2384	95.36	1479.657
Weekend, day	25	2528	101.12	2434.61
Weekend, evening	25	3074	122.96	2608.457
ANOVA
Source of variation	ss	df	MS	F	P-value	F crit
Between groups	20449.23	3	6816.41	3.488671	0.018695	2.699393
total	208020.8	99

The null hypothesis is rejected – because p-value = 0.018695 is less than α=0.05