Question

R4 422 Closed sw1 at t=0 and opened again at t=0.12. It is open for a very long time. 1.Vc=? at t=0 2.Vc=? at t=0..12 3.Vc=? at t=0.24 SW1 w + V1 4A 4 11 4 A R1 6Ω R3 4 Ω C1 80 mF Vc R2 102 +1 20 V

Answer 1

The problem is solved below.

1. Ve/e=0 w 42 V Swi Apply KCL at vi 42 201 10 44 62 SOMET 20-VI V 10 V Vi 4 -5 » V, - 100V + 10 Vc 100v at t=0 2. Vc = ? at t-0-12 Apply KCL at v, at to V-20 -4 V-20 + + Vi 6 Vi 10 + + + 420 -V 23 4+10 = 14 I to +5+ Ş) 41 420 V, () - ✓ 23 Т. Reg iar → V (H) = Vc (0) -Haco . (V((O) - Vese + abr 30 23 4 4 & Reg + + 6 10 - t/30450 Vi (t) = 420 23 7 100 420 23 + - 420 e 0:12 at t=0-12 W. (1) = 0+ (420) e com = 11v t=0.12 Vc = 17V at

42 3. Ve = ? at t=0.24 Now, Vi 0 = 17V Sour 42 102 Reg V(x) = 100 v Reg 20 ។ + lo 1 4 4+6 -(t-0-12) Vo(t) = Vc (00) + ( Vc (6) - V.()) e Reg C (0.24-0.12) + (17-100 e 7 20 xson 100 = 15.667 =) | Vc = 15.667 v at t=0.24