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Consider two blocks A and B that are insulated from all sides except the right side. There is internal heat generation (qa= 1

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D Solution? ir 7 TBS KB Inculated EVA = 10 kw/m3 K LAK LB Data given VA = lotwim To = 25 c = 258k h = low/m²c LB = 20cm LA =BCG nro T-To - 448k 3 = A=o.im T = Tint Put Bar in Egh BO To = 448 = - abg xo + xo + 2 C2 = 448 - © ZKA BC - Vg (0-11 ²+ Grolbut a-o in & ③ Tint = - so +0+ 448 – – So + 448 – Equating heat flux e o Tint - TBS - hxax ( Tes - Ta) UB KBA first take Tintat n=o Insulated it meary (Tint - Tal (Vg) AX AX LA = It ha AX (Tint - 298) lotxAX 0.1 = 0.2 + to 103x (0.04+ 0.1) - Tint -29Remaining part Boundary conditions 2K T= - Vg n²+ Ch+C2 Be 0 =0 T=To = 448K BC ③ x=LA T= Tint BC ③ n=0 Q=0 ck la nostra (dIj

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