A 2.0kg ball and a 4.0kg ball are connected by a 3.0m long rigid, massless rod. The rod and balls are rotating clockwise about its center of gravity at 16rpm .
What torque will bring the balls to a halt in 9.0s ? Express your answer using two significant figures. Assume the counterclockwise rotation as positive.
Here ,
m1 = 2 Kg
m2 = 4 kg
Here ,
Xcom = 2*3/(2+4)
Xcom = 1 m
Here ,
I = 2*2^2 + 4*1^2
I = 12 Kg.m/s
the moment of inertia is 12 Kg.m/s
Here , wf = 16 rpm
wf = 1.675 rad/s
Now , Using second law of motion
Torque , T = 12 * (-1.675 + 0)/9
T = -2.23 N.m
the torque required is -2.23 N.m
A 2.0kg ball and a 4.0kg ball are connected by a 3.0m long rigid, massless rod....
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