(a) Because the electric field is constant, V = Electric field*distance = E*r
(b) The capacitance of the capacitor is C = ε0*area/distance = ε0*π(d^2/4)/r = ε0*π*d^2/4r
The magnitude of the charge on each disk is therefore
Q = C∆V = [ ε0*π*d^2/4r]*E*r = ε0*E*π*d^2/r
Two disks of diameter d are spaced a distance r apart to form a parallel-plate capacitor....
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Two 2.1-cm-diameter-disks spaced 1.8 mm apart form a parallel-plate capacitor. The electric field between the disks is 4.3×105 V/m . How much charge is on each disk? q1?, q2?
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