here,
1)
mass of sled , men and rock , M = 97.5 kg
mass of rock , m = 0.32 kg
initial speed of men , u = 0.49 m/s
final speed of rock , v2 = 17 m/s
let the final speed of man be v1
using conservation of momentum
M * u = (M - m) * v1 + m * v2
97.5 * 0.49 = (97.5 - 0.32) * v1 + 0.32 * 17
solving for v1
v1 = 0.44 m/s
the final speed of sled is 0.44 m/s in forward direction
2)
mass of sled , men and rock , M = 97.5 kg
mass of rock , m = 0.32 kg
initial speed of men , u = 0.49 m/s
when the rock is thrown in opposite direction
final speed of rock , v2 = - 17 m/s
let the final speed of man be v1
using conservation of momentum
M * u = (M - m) * v1 + m * v2
97.5 * 0.49 = (97.5 - 0.32) * v1 - 0.32 * 17
solving for v1
v1 = 0.55 m/s
the final speed of sled is 0.55 m/s in forward direction
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